Argo 02 blueprints. Calculation of the spar for strength. Aileron deflection angles, deg

  • 02.03.2021

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Description of the ship "Argo-2"

Motor ship "Argo-2" perfect for those who appreciate comfort, quality and cosiness and for everyone who wants to spend an unforgettable holiday on board a comfortable liner, enjoying the splashing of the waves of the Moscow River and amazing views of the capital. Renting the motor ship Argo-2 is suitable for weddings, birthdays and corporate parties.

Technical characteristics of the ship "Argo-2"

  • Project: 81080 Moskovsky
  • Place of construction: Moscow shipbuilding and ship repair plant
  • Year built: 1989
  • Refurbished in 2009
  • Width, m: 6
  • Length, m: 33
  • Board height, m: 2.6
  • Displacement, t: 167.88
  • Draft, m: 1.31
  • Passenger capacity: 70 people
  • Postscript: Moscow

The layout of the ship "Argo-2"

  • Hall-restaurant;
  • upper deck (tarpaulin and open);
  • veranda in the bow;
  • 4 cabins, one of them is guest;
  • galley.

The interiors of the ship "Argo-2"

The banquet hall of the ship is made in stylish interior solutions, decorated with wood and other natural materials. Laminate on the floor. The staircase leading from the banquet hall to the ship's hold is fenced off with a carved rim. But the details give a special charm to the interior, of which there are a huge number: figurines, models, panels and much more. In general, everything is simple and very nice.

The restaurant is connected by a passage to the bow deck, where there is a seating area with wicker sofas and armchairs. The upper deck is equipped with a summer veranda with appropriate deck furniture. The protective awning provides comfortable rest under any weather conditions. The floor of the deck is covered with a non-slip coating.

Equipment of the ship "Argo-2"

  • audio and video equipment;
  • air conditioners;
  • plasma panel;
  • TV/DVD;
  • karaoke;
  • microphones.

Meals on board the ship "Argo-2"

Argo-2 has its own professional chef, whose skills have already been appreciated by many, including the stars of domestic show business. There are several menu options: banquet, buffet, picnic. The author's cuisine is based on the culinary traditions of European, Russian, Caucasian cuisine.

Advantages of the ship "Argo-2":

  • the original layout of the ship;
  • modern design an interior that is suitable for any format of the event;
  • equipment with modern audio and video equipment;
  • powerful air conditioners in the banquet hall.

Developers: E. Ignatiev, Y. Gulakov and A. Abramov
Country: USSR
First flight: 1987

Light single-seat aircraft "Argo-02" was built by craftsmen from the city of Kalinin E. Ignatiev, Yu. Gulakov and A. Abramov. For the manufacture of "Argo-02" used a simple pine, plywood, canvas. The authors used for some reason a scheme of a good cantilever low-wing aircraft, forgotten by do-it-yourselfers, and a simple communist motor was installed.

At the SLA-87 rally, Argo-02 flights demonstrated that the Kalinin home-made flies better than some solid aircraft with imported engines.

"Argo-02" is an ultra-light training cantilever low-wing aircraft of good wood construction with a cantilever tail unit. The aircraft has a spring-type landing gear with a tail support.

The power plant is a two-stroke 2-cylinder air-cooled engine RMZ-640, which, through a V-belt gearbox, drives a two-blade wood monoblock air propeller. The aircraft control system is of the usual type. The cockpit is equipped with aerobatic team devices and engine operation control devices.

The fuselage is made of wood, of a cross-truss construction, with spars made of wood laths with a section of 18 x 18 mm. Behind the cockpit, on top of the fuselage, there is a light fairing, the base of which is stringers and foam diaphragms. There is also a fairing in the front of the fuselage, in front of the cockpit it is made of skin and wooden diaphragms made of sheet duralumin 0.5 mm thick.

the tail section and the cockpit of the fuselage near the stabilizer mount are sheathed with plywood 2.5 mm thick. All other surfaces of the fuselage are fabric covered.

According to the technical commission and the calculations of the authors, the operational overload of the Argo-02 was equal to 3, which is quite enough for flights on short routes and circles. Aerobatics is strictly contraindicated for this device. Amateur aircraft designers should not forget about this ...

On August 18, 1990, while performing a demonstration flight at a celebration dedicated to the Day of the Air Fleet, Yuri Gulakov led the Argo into another coup. This time, the speed was slightly higher than the simple one, and the large operational overload, of course, far exceeded the calculated "troika". As a result, the wing of the Argo broke apart in the air, and the pilot died in front of the assembled spectators.

Length, m: 4.55
Wingspan, m: 6.3
Wing area, m2: 6.3
Weight, kg
- deserted: 145
- takeoff: 235
Specific load on the wing, kgf / m2: 37.3
Engine: RMZ-640
Max speed, km/h: 160
Cruise speed, km/h: 120
Stall speed, km/h: 72
Rate of climb, m/s: 2.

Light aircraft "Argo-02" at the rally SLA-89.

The two-deck motor ship of the luxury category can accommodate 50 people on board in the banquet format and 70 passengers in the buffet table. The motor ship-restaurant is a modern version of a banquet ship, which offers guests unusually designed interiors, great musical and lighting opportunities, as well as a well-thought-out climate control system.

The length of 36 meters makes the vessel quite maneuverable, and the draft of 1.5 meters allows it to approach almost all ports of the capital and the region. The speed developed by the vessel reaches 24 km/h, which is a high indicator for ships of this class.

Advantages of the ship "Argo-2"

  • One of the most popular motor ships of the capital's fleet.
  • Modern multidisciplinary equipment.
  • The interiors are made in the refined Provence style.
  • organization of events at a high level.

Interiors and layout of the ship "Argo-2"

On the upper deck of the ship there is a spacious area for a summer cafe. The necessary furniture and audio equipment is installed there. The capacity of this site is 40 seats. The site is outdoors, but if necessary, it is closed with an awning. There is a zone for decorating a dance floor and all the conditions for organizing light and music shows.

The ship's banquet hall is located on the lower deck. There are tables for four people in the hall, which, if necessary, can be moved and chairs. There are also air conditioners. Guests have the opportunity to use the karaoke system. On the central wall there is an LCD panel for demonstrating the video sequence. In addition, well-functioning lighting equipment is available to complement the musical numbers.

The hall is divided into small areas using elegantly designed props. The flooring is oak parquet. Window openings are decorated with tulle. The interior is designed using dark shades of wood and beige textile elements.

From the banquet hall there is an exit to the bow area of ​​the deck, where an open area is equipped for holding small receptions. In the presence of all the furniture necessary for a comfortable pastime. The deck space allows you to additionally install the necessary furniture and musical equipment.

The descents on the ship are designed in the form of stairwells with railings decorated with carved balusters in a classic style.

Catering and additional services

The ship's attendants are ready to offer various design options for the banquet hall and other venues, taking into account the specifics of the celebration. It is possible to serve tables with fresh flowers and floral compositions. The color scheme of the banquet decoration can also be changed at the request of the customer, which is discussed separately when renting a ship.

Ordering the decor of the entire ship involves the use various materials, including silk ribbons, garlands of balloons, natural plant elements, LED compositions.

Catering and passenger service during the banquet on the ship is organized by the crew. At the request of the customer, it is possible to invite your own team on board service personnel. In this case, a preliminary agreement with the administration of the ship is required.

The main characteristics of the ship "Argo-2"

  • The Moskovsky project was reconstructed in 2009.
  • Length - 33 m;
  • Width - 6 m;
  • Draft - 1.3 m.

ATTENTION!!!


The calculation method below, as well as all the data
obtained using this technique ARE NOT
any instruction or guide to action,
and are provided here for informational purposes only.
The author assumes no responsibility for the use of the data below.



I'm just telling you how I build the plane myself. And now closer to the point.

The spar consists of two shelves, between which there are bulkheads and which are sewn on both sides with millimetric plywood. Thus, for our case, to calculate the spar for strength means to calculate the height of each of the shelves. Moreover, this height is different for the upper and lower shelves. Now I will explain why.

During normal flight, lifting force, which tries to bend the wing up:

And we see that the upper shelf is trying to shrink, and the lower shelf is trying to stretch. Shelves will be made of pine. And pine is remarkable in that it has a very high tensile strength. But not very good indicator compressive strength. Thus, for the upper shelf, which works in compression, a shelf with a larger section is needed, compared to the lower one, which works in tension.

Now directly calculation.

As initial data, we need the following values:
Gvzl - take-off weight. Original 235 kg. I took 250 kg. (I myself already weigh about a hundred).
Gcr - wing weight. As in the original, I accept 13 kg.
ne - the value of the operational overload. As in the original, I accept equal to 3.
f - safety factor. Recommended value: 1.2 - 1.5. But in Chumak's book "Calculation, design and construction of ultralight aircraft" it is recommended to take a value in the range of 1.5 - 2.0. I decided to take a value of 1.8.
nр - destructive overload value. The value is obtained by multiplying ne by f. That. we get the value 5.4.
Lcr - wing span. For my case - 6.1 meters.
Lkons - the length of one console = 2.775 meters.
H is the height of the spar. To do this, subtract the thickness of the rib rails from the maximum profile height, which will go above and below the spar. Those. 155 - 5 - 5 = 145mm. For further calculations, we need a value in centimeters. Those. we will use the value of 14.5 cm.
b - spar width - 40 mm = 4 cm.
T/t - the ratio of the height of the lower shelf to the top. The recommended value is 1.75.

The essence of the calculation is to calculate the cross section of the spar flanges, which will collapse only when the destructive overload is reached. Those. according to our calculations, when an overload of 5.4g is reached, the spar will fall apart. In this case, the normal operating overload is 3. And it is dangerous to exceed this value. The coefficient f = 1.8 takes into account inaccuracies and minor errors in the manufacture of the spar and gives us a margin of 2.4g. But, again, it is better not to exceed the value of 3.

We will calculate the cross section at five points. To do this, we divide the wing into five equal sections.


It does not matter to calculate the load at the last unnumbered point. Because in this place, the spar does not experience any load and is only necessary to maintain the integrity of the entire structure.

The calculation itself.

1. Determine the linear breaking load on the wing. To do this, subtract the mass of the wing from the mass of the aircraft, multiply everything by the value of the destructive overload and divide all this by the span of the wing. That. we get the value of the load per meter of wing length (I won’t use the word “destructive”, otherwise it’s somehow not fun). For our case, we get:

q \u003d (Gvzl - Gkr) * nr / Lkr \u003d (250 - 13) * 5.4 / 6.1 \u003d 209.8 kg / mp.


There is one small question here, the answer to which I have not found. The fact is that we divide the load by the span of the entire wing. This value is the sum of the length of the two consoles and the width of the fuselage. And the question is, is it necessary to include the width of the fuselage in the calculation? Or was it more correct to distribute the load only on the wings? On the forums where I asked the question, opinions were divided. Therefore, I decided to do it all the same as in the original - to include the width of the fuselage in the wingspan. Just information for general development: in modern fighters, the fuselage creates 30% or more of the total lift.

2. In the previous step, we calculated the value of the load per linear meter of the wing. Now let's calculate the load value for each of the five points of the wing.

At the point

q0 = q * Lcons = 209.8 * 2.775 = 582.2.

On a section at a point

q1 \u003d q * Lcons * 4 / 5 \u003d 209.8 * 2.775 * 4 / 5 \u003d 465.6.

Similarly for points 2 , 3 , 4 :

q2 = 209.8 * 2.775 * 3 / 5 = 349.3

q3 = 209.8 * 2.775 * 2 / 5 = 232.9

q4 = 209.8 * 2.775 * 1/5 = 116.4

3. For each of the points, we determine the value of the bending moment according to the formula:

M0 = q0 * Lcons / 2 = 582.2 * 2.775 / 2 = 807.8 kg/m

Similarly for the other points:

M1 = 465.6 * 2.775 * (4 / 5) / 2 = 516.8 kg/m

M2 = 349.3 * 2.775 * (3 / 5) / 2 = 290.8 kg/m

M3 = 232.9 * 2.775 * (2 / 5) / 2 = 129.3 kg/m

M3 = 116.4 * 2.775 * (1 / 5) / 2 = 32.3 kg/m

4. Using the moments calculated earlier, we calculate the value of 58.3E using the formula:

58.3E = M / (b * H * H).

To be honest, I really don’t remember what the value of 58.3E is, but we will plot this value on the chart in the next paragraph.

In this case, you need to pay attention to the fact that the value of the bending moment already needs to be taken not in kg / m, but in kg / cm. Those. increase this value by a factor of 100.

We get for each of the points:

58.3E_0 = 807.8 * 100 / (4 * 14.5 * 14.5) = 96.05

58.3E_1 = 516.8 * 100 / (4 * 14.5 * 14.5) = 61.45

58.3E_2 = 290.8 * 100 / (4 * 14.5 * 14.5) = 34.58

58.3E_3 = 129.3 * 100 / (4 * 14.5 * 14.5) = 15.4

58.3E_4 = 32.3 * 100 / (4 * 14.5 * 14.5) = 3.84

5. Plot the values ​​obtained in the previous step on the graph below and get the T/H values

As can be seen from the graph, it makes no sense to make calculations for points 3 and 4 - the values ​​go beyond the graph.